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4y^2-y=11
We move all terms to the left:
4y^2-y-(11)=0
We add all the numbers together, and all the variables
4y^2-1y-11=0
a = 4; b = -1; c = -11;
Δ = b2-4ac
Δ = -12-4·4·(-11)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{177}}{2*4}=\frac{1-\sqrt{177}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{177}}{2*4}=\frac{1+\sqrt{177}}{8} $
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